Two rods are connected as shown. rods are of same length and same cross sectional area. In steady st

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10-2.Transmission of Heat

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Two rods are connected as shown. The rods are of same length and same cross sectional area. In steady state, the temperature $\left( \theta \right)$ of the interface will be........ $^oC$

A

$60$

B

$73.3$

C

$46.7$

D

$37.3$

Solution

$\frac{\mathrm{d} \mathrm{Q}_{1}}{\mathrm{dt}}=\frac{\mathrm{d} \mathrm{Q}_{2}}{\mathrm{dt}}$

$\frac{2 \mathrm{k} \mathrm{A}(100-\mathrm{T})}{\ell}=\frac{\mathrm{k} \mathrm{A}(\mathrm{T}-20)}{\ell}$

$200-2 \mathrm{T}=\mathrm{T}-20$

$3 \mathrm{T}=220$

$\mathrm{T}=\frac{220}{3}=73.3 \mathrm{K}$

Standard 11

Physics

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